H93 · Higher tier · A11, A18

Completing the square and turning points

3 marksHigherGrade 6Non-calculator

y=x2+6x+2y = x^2 + 6x + 2
(a)
Write x2+6x+2x^2 + 6x + 2 in the form (x+a)2+b(x + a)^2 + b.
(2 marks)
(b)
Write down the coordinates of the turning point of y=x2+6x+2y = x^2 + 6x + 2.
(1 mark)

2 marksHigherGrade 6CalculatorProblem solving

Find the coordinates of the turning point of y=x2+10x+17y = x^{2} + 10x + 17.
(2 marks)

4 marksHigherGrade 7Non-calculatorProblem solving

The curve y=x2+px+qy = x^2 + px + q has a turning point at (5,−3)(5, -3).
(a)
Find the value of pp.
(2 marks)
(b)
Find the value of qq.
(2 marks)

3 marksHigherGrade 7Non-calculatorProblem solving

A rectangular enclosure is built against a straight wall. Exactly 60 m of fencing is used for the other three sides. Find the greatest possible area of the enclosure.
(3 marks)
m²

4 marksHigherGrade 7Non-calculator

y=x2−6x+10y=x^2-6x+10.
(a)
Write y in completed-square form.
(2 marks)
(b)
Find the minimum point.
(2 marks)

5 marksHigherGrade 7Non-calculatorProblem solving

Exactly 24 m of fencing forms three sides of a rectangle against a straight wall. Each side perpendicular to the wall has length x.
(a)
Write the area in completed-square form.
(3 marks)
(b)
Find the greatest possible area.
(2 marks)
m²

5 marksHigherGrade 7Non-calculator

x2+10x+18=0x^2+10x+18=0.
(a)
Solve by completing the square. Give exact answers.
(3 marks)
(b)
Find the sum of the two roots.
(2 marks)

4 marksHigherGrade 7Non-calculator

Consider y=−x2+8x−11y = -x^2 + 8x - 11.
(a)
Write y in the form a−(x−b)2a - (x - b)^2.
(2 marks)
(b)
Write down the coordinates of the maximum point of the curve.
(1 mark)
(c)
Explain why −x2+8x−11≤5-x^2 + 8x - 11 \le 5 for every value of x.
(1 mark)

5 marksHigherGrade 8Non-calculator

2x2−12x+52x^2 - 12x + 5
(a)
Write 2x2−12x+52x^2 - 12x + 5 in the form a(x+b)2+ca(x + b)^2 + c.
(3 marks)
(b)
Hence solve 2x2−12x+5=02x^2 - 12x + 5 = 0. Give your answers in exact form.
(2 marks)

4 marksHigherGrade 8Non-calculatorProblem solving

E=x2−8x+20E = x^2 - 8x + 20
(a)
By completing the square, show that E>0E > 0 for all values of xx.
(2 marks)
(b)
Find the greatest value of 1x2−8x+20\dfrac{1}{x^2 - 8x + 20}.
(2 marks)

Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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