Worksheets · Foundation and Higher

Like terms and algebraic index rules

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 2 marks

    (a) Simplify 7m + 3n −- 2m + 5n. (2)

  2. Question 2Non-calculator · 4 marks

    xx and yy are non-zero. Consider 6x5y33x2y\frac{6x^5y^3}{3x^2y}.

    (a) Simplify the expression. (2)

    (b) Evaluate the simplified expression when x = −2 and y = 3. (2)

  3. Question 3Non-calculator · 6 marks

    Answer each part without a calculator.

    (a) Show that (3x2y)39xy2=3x5y\dfrac{(3x^2y)^3}{9xy^2} = 3x^5y (2)

    (b) 2x×4y=2102^x \times 4^y = 2^{10} and x+y=7x + y = 7. Find the value of yy. (4)

Answers and marks

Question 1

(a) 5m+8n5m + 8n

  • M1 Establishing 7m−2m+3n+5n7m-2m+3n+5n or an equivalent valid method.
  • A1 Correct answer: 5m+8n5m + 8n

Question 2

(a) 2x3y22x^{3}y^{2}

  • M1 Divide the coefficients and subtract powers of each matching base.
  • A1 Correct answer: 2x3y22x^{3}y^{2}

(b) −144-144

  • M1 Keep brackets around the negative base raised to an odd power.
  • A1 Correct answer: −144-144

Question 3

(a) 27x6y39xy2=3x5y\frac{27x^6y^3}{9xy^2} = 3x^5y

  • M1 Expanding the numerator to 27x6y327x^6y^3.
  • A1 Dividing correctly to reach 3x5y3x^5y with each index shown.

(b) y=3y = 3

  • P1 Writing 4y4^y as 22y2^{2y}.
  • P1 Forming the equation x+2y=10x + 2y = 10.
  • P1 Solving with x+y=7x + y = 7 (subtracting or substituting).
  • A1 The correct answer, y=3y = 3.

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Like terms and algebraic index rules

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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