Worksheets · Foundation and Higher

Linear equations, including both sides

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Calculator · 2 marks

    (a) Solve 6x + 5 = 47. (2)

  2. Question 2Non-calculator · 4 marks

    A number x satisfies 3(4x−4)=2(4x+2)+43(4x-4)=2(4x+2)+4.

    (a) Solve the equation. (3)

    (b) Describe a check for your solution. (1)

  3. Question 3Non-calculator · 6 marks

    Show clear algebraic working.

    (a) Solve x+43−x−24=2\dfrac{x + 4}{3} - \dfrac{x - 2}{4} = 2. You must show your working. (3)

    (b) The mean of the four expressions 2x+12x + 1, 3x−23x - 2, x+7x + 7 and 1010 is equal to 3x−13x - 1. Find the value of xx. You must show your working. (3)

Answers and marks

Question 1

(a) 77

  • M1 Establishing 6x=426x=42 or an equivalent valid method.
  • A1 Correct answer: 77

Question 2

(a) 55

  • M1 Expand both brackets and preserve every sign.
  • M1 Collect x terms on one side and constants on the other.
  • A1 Correct answer: 55

(b) Substitute the value into both original bracketed sides and confirm that the two totals are equal.

  • C1 Correct conclusion with supporting reasoning: Substitute the value into both original bracketed sides and confirm that the two totals are equal.

Question 3

(a) x=2x = 2

  • M1 Multiplying through by 12 (or a common multiple) to clear both fractions, including the 2 on the right.
  • M1 Expanding to 4x+16−3x+64x + 16 - 3x + 6.
  • A1 The correct answer, x=2x = 2.

(b) x=103x = \dfrac{10}{3}

  • P1 Finding the total 6x+166x + 16.
  • P1 Forming 6x+164=3x−1\frac{6x + 16}{4} = 3x - 1 (or 6x+16=4(3x−1)6x + 16 = 4(3x - 1)).
  • A1 x=103x = \frac{10}{3} (or 3133\frac{1}{3}).

Get your working marked

Linear equations, including both sides

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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