Worksheets · Foundation and Higher

Equations of lines and parallel lines

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 3 marks

    Answer each part.

    (a) Write down the equation of the line that is parallel to y=3x+2y = 3x + 2 and passes through (0,−5)(0, -5). (2)

    (b) Which line is parallel to y=4x−1y = 4x - 1? (1)

    1. y=4x+3y = 4x + 3
    2. y=x−1y = x - 1
    3. y=−4x−1y = -4x - 1
    4. y=14xy = \frac{1}{4}x
  2. Question 2Non-calculator · 4 marks

    Lines L1 and L2 have equations y=3x−2y = 3x - 2 and 6x−2y=76x - 2y = 7.

    (a) Show that L1 and L2 are parallel. (2)

    (b) Find the coordinates of the point where L2 crosses the x-axis. (2)

  3. Question 3Non-calculator · 5 marks

    Line L1L_1 has equation 2y−6x=82y - 6x = 8. Line L2L_2 is parallel to L1L_1 and passes through the point (4,5)(4, 5).

    (a) Find an equation of L2L_2. (3)

    (b) Find the coordinates of the point where L2L_2 crosses the xx-axis. (2)

Answers and marks

Question 1

(a) y=3x−5y = 3x - 5

  • B1 Gradient 3 in an equation y=3x+cy = 3x + c.
  • B1 The correct answer, y=3x−5y = 3x - 5.

(b) y=4x+3y = 4x + 3

  • B1 The correct answer, y=4x+3y = 4x + 3.

Question 2

(a) L2 rearranges to y = 3x - 3.5, so both lines have gradient 3.

  • M1 Rearrange L2 into the form y = mx + c.
  • C1 Correct conclusion with supporting reasoning: L2 rearranges to y = 3x - 3.5, so both lines have gradient 3.

(b) (7/6,0)(7/6,0)

  • M1 Substitute y = 0 into the equation of L2.
  • A1 Correct answer: (7/6,0)(7/6,0)

Question 3

(a) y=3x−7y = 3x - 7

  • P1 Rearranging L1L_1 to find the gradient 3.
  • P1 Substituting (4,5)(4, 5) into y=3x+cy = 3x + c.
  • A1 The correct answer, y=3x−7y = 3x - 7.

(b) (73,0)\left(\frac{7}{3}, 0\right)

  • M1 Setting y=0y = 0.
  • A1 (73,0)\left(\frac{7}{3}, 0\right).

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Equations of lines and parallel lines

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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