Worksheets · Foundation and Higher

Term rules, special and geometric sequences

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 4 marks

    Here are the first four terms of a sequence: 5,9,13,175, 9, 13, 17.

    (a) Write down the next term of the sequence. (1)

    (b) Which is the term-to-term rule? (1)

    1. Add 4
    2. Multiply by 4
    3. Add 5

    (c) Is 50 a term in this sequence? You must show how you get your answer. (2)

    1. Yes
    2. No
  2. Question 2Non-calculator · 5 marks

    A sequence starts with 3. Each new term is found by multiplying the previous term by 2 and adding 3.

    (a) Find the fourth term. (3)

    (b) Find the term immediately before the first term if the same rule is used. (2)

  3. Question 3Non-calculator · 5 marks

    The nnth triangular number is Tn=n(n+1)2T_n = \dfrac{n(n + 1)}{2}.

    (a) Show that the sum of two consecutive triangular numbers, Tn+Tn+1T_n + T_{n + 1}, is always a square number. (3)

    (b) A geometric sequence has first term 81 and common ratio 23\frac{2}{3}. Work out the first term of the sequence that is not a whole number. (2)

Answers and marks

Question 1

(a) 2121

  • B1 The correct answer, 2121.

(b) Add 4

  • B1 The correct answer, Add 4.

(c) No: the terms are 1 more than a multiple of 4, and 50 is not.

  • M1 Continuing the sequence past 50 (49 and 53), or noticing each term is 1 more than a multiple of 4.
  • C1 "No", with 49 and 53 shown (or 50 not 1 more than a multiple of 4).

Question 2

(a) 4545

  • M1 Generate the second and third terms in order.
  • M1 Apply the rule once more for the fourth term.
  • A1 Correct answer: 4545

(b) 00

  • M1 Reverse the rule: subtract 3, then divide by 2.
  • A1 Correct answer: 00

Question 3

(a) Tn+Tn+1=(n+1)2T_n + T_{n+1} = (n + 1)^2

  • M1 Writing Tn+1=(n+1)(n+2)2T_{n+1} = \frac{(n + 1)(n + 2)}{2}.
  • M1 Adding over a common denominator or factorising out (n+1)(n + 1).
  • C1 Reaching (n+1)2(n + 1)^2 and stating it is a square.

(b) 323\frac{32}{3}

  • P1 Generating at least three terms correctly (54, 36, 24).
  • A1 323\frac{32}{3} (or 102310\frac{2}{3}).

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Term rules, special and geometric sequences

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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