Worksheets · Foundation and Higher

Compass constructions and loci

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 4 marks

    Maya is bisecting angle ABCABC with a ruler and compasses.

    (a) Which is her first step? (1)

    1. Join A to C and mark its midpoint
    2. With the compass point on B, draw an arc crossing both arms
    3. Measure the angle with a protractor and halve it

    (b) Explain why the arcs drawn from the two points on the arms must have the same radius. (1)

    (c) On paper, draw an angle of about 70∘70^\circ and label it ABCABC. Use a ruler and compasses to construct the bisector of angle ABCABC. You must show all your construction arcs. Then write down, one step per line, what you drew, and check your drawing against the mark scheme. (2)

  2. Question 2Non-calculator · 4 marks

    A is (−3,0)(-3,0) and B is (3,0)(3,0). A point P is equidistant from A and B and is 4 units from the x-axis.

    (a) Find both possible coordinates of P. (3)

    (b) Describe the two loci whose intersections give the answers. (1)

  3. Question 3Non-calculator · 5 marks

    AA is the point (−2,1)(-2, 1) and BB is the point (4,1)(4, 1). The point PP lies on the perpendicular bisector of ABAB. PP is also on the bisector of the angle between the positive xx-axis and the positive yy-axis.

    (a) Find the coordinates of PP. (3)

    (b) Work out the shortest distance from PP to the line y=7y = 7. (1)

    (c) Explain why the shortest distance from PP to the line y=7y = 7 is along a line perpendicular to y=7y = 7. (1)

Answers and marks

Question 1

(a) With the compass point on BB, draw an arc crossing both arms of the angle.

  • B1 The arc centred on BB.

(b) The crossing point must be the same distance from both points, so it lies on the line of symmetry of the angle.

  • C1 Linking equal radii to the crossing point being the same distance from both arm points (symmetry of the construction).

(c) An arc centred on BB crossing both arms at XX and YY; equal arcs from XX and YY crossing at ZZ; the line BZBZ, with every arc left visible.

  • B1 Arcs of equal radius drawn from two points on the arms that are the same distance from BB, crossing inside the angle.
  • B1 The bisector drawn from BB through the crossing point, within 2∘2^\circ of the true bisector, with all construction arcs shown.

Question 2

(a) (0,4)(0,4) and (0,−4)(0,-4)

  • M1 The perpendicular bisector of AB is the y-axis.
  • M1 Being the given distance from the x-axis allows either sign of y.
  • A1 Correct answer: (0,4)(0,4) and (0,−4)(0,-4)

(b) The perpendicular bisector x = 0 and the two lines y = 4, y = -4.

  • C1 Correct conclusion with supporting reasoning: The perpendicular bisector x = 0 and the two lines y = 4, y = -4.

Question 3

(a) (1,1)(1, 1)

  • P1 The perpendicular bisector x=1x = 1.
  • P1 The angle bisector y=xy = x.
  • A1 Correct answer: (1,1)(1, 1).

(b) 6 units

  • B1 Correct answer: 6.

(c) Any other route is the hypotenuse of a right-angled triangle with the perpendicular as a shorter side.

  • C1 A correct argument: any slanted route is the hypotenuse of a right-angled triangle, so it is longer than the perpendicular.

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Compass constructions and loci

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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