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Quadratic sequence nth terms

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 3 marks

    Here are the first five terms of a quadratic sequence: 3,8,15,24,353, 8, 15, 24, 35.

    (a) Find an expression for the nnth term. (3)

  2. Question 2Non-calculator · 5 marks

    A quadratic sequence has second difference 6, second term 19 and fifth term 79.

    (a) Find its nth term. (3)

    (b) Find the first position whose term is greater than 1189. (2)

  3. Question 3Calculator · 5 marks

    (a) A quadratic sequence has constant second difference 2. Its second term is 9 and its fifth term is 42. Starting with the first term at n = 1, find the position of the first term greater than 1000. (5)

Answers and marks

Question 1

(a) n2+2nn^2 + 2n

  • M1 Finding the second difference 2 and the term n2n^2.
  • M1 Subtracting n2n^2 to get the linear part 2,4,6,…2, 4, 6, \ldots
  • A1 The correct answer, n2+2nn^2 + 2n.

Question 2

(a) 3n2−n+93n^{2}-n+9

  • M1 Use the second difference to write the form an2+bn+can^2 + bn + c.
  • M1 Use the two known terms to solve for the linear coefficient and constant.
  • A1 Correct answer: 3n2−n+93n^{2}-n+9

(b) 2121

  • M1 The 20th term equals the threshold and all later differences are positive.
  • A1 Correct answer: 2121

Question 3

(a) 3030

  • P1 Establishing 2b+c=52b+c=5 or an equivalent valid method.
  • P1 Establishing 5b+c=175b+c=17 or an equivalent valid method.
  • P1 Establishing 292+4×29−329^{2}+4\times 29-3 or an equivalent valid method.
  • P1 Establishing 302+4×30−330^{2}+4\times 30-3 or an equivalent valid method.
  • A1 Correct answer: 3030

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Quadratic sequence nth terms

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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