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Sine rule and the ambiguous case

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Calculator · 2 marks

    In triangle ABCABC, angle A=40∘A = 40^\circ, angle B=65∘B = 65^\circ and BC=8BC = 8 cm.

    (a) Work out the length of ACAC. Give your answer correct to 3 significant figures. (2)

  2. Question 2Calculator · 5 marks

    In triangle ABC, angle A is 30 degrees, BC = 8 cm and AC = 12 cm. There are two possible triangles.

    (a) Find both possible values of angle B, to 1 decimal place. (3)

    (b) Find the larger possible area to 3 significant figures. (2)

  3. Question 3Calculator · 3 marks

    (a) In triangle ABC, AB = 12 cm, AC = 9 cm and angle ABC = 35∘.35^\circ. There are two possible triangles. Work out the larger possible area. Give your answer to 3 significant figures. You must show your working. (3)

Answers and marks

Question 1

(a) 11.3 cm

  • M1 A correct sine-rule statement pairing each side with its opposite angle.
  • A1 Correct answer: 11.3 cm.

Question 2

(a) 48.6 degrees and 131.4 degrees.

  • P1 Apply the sine rule to obtain sin B.
  • P1 Use the acute inverse-sine angle and its supplement.
  • A1 Correct answer: 48.6 degrees and 131.4 degrees.

(b) 47.147.1 cm²

  • P1 Find each included angle C and compare the resulting triangle areas.
  • A1 Correct answer: 47.147.1 cm²

Question 3

(a) 53.853.8 cm²

  • P1 Establishing 12×sin⁡(35)/912\times \sin(35)/9 or an equivalent valid method.
  • P1 The two possible angles C are 49.886408...∘49.886408...^\circ and 130.113591...∘.130.113591...^\circ. Hence angle A is 95.113591...∘95.113591...^\circ or 14.886408...∘.14.886408...^\circ.
  • A1 Correct answer: 53.853.8 cm²

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Sine rule and the ambiguous case

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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