Sine rule and the ambiguous case
3 exam-style questions. Answers and the mark for each step are on the last page.
- Question 1
In triangle , angle , angle and cm.
(a) Work out the length of . Give your answer correct to 3 significant figures.
- Question 2
In triangle ABC, angle A is 30 degrees, BC = 8 cm and AC = 12 cm. There are two possible triangles.
(a) Find both possible values of angle B, to 1 decimal place.
(b) Find the larger possible area to 3 significant figures.
- Question 3
(a) In triangle ABC, AB = 12 cm, AC = 9 cm and angle ABC = There are two possible triangles. Work out the larger possible area. Give your answer to 3 significant figures. You must show your working.
Answers and marks
Question 1
(a) 11.3 cm
- M1 A correct sine-rule statement pairing each side with its opposite angle.
- A1 Correct answer: 11.3 cm.
Question 2
(a) 48.6 degrees and 131.4 degrees.
- P1 Apply the sine rule to obtain sin B.
- P1 Use the acute inverse-sine angle and its supplement.
- A1 Correct answer: 48.6 degrees and 131.4 degrees.
(b) cm²
- P1 Find each included angle C and compare the resulting triangle areas.
- A1 Correct answer: cm²
Question 3
(a) cm²
- P1 Establishing or an equivalent valid method.
- P1 The two possible angles C are and Hence angle A is or
- A1 Correct answer: cm²