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Cosine rule for sides and angles

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Calculator · 3 marks

    In triangle ABCABC, AC=7AC = 7 cm, AB=9AB = 9 cm and angle BAC=52∘BAC = 52^\circ.

    (a) Work out the length of BCBC. Give your answer correct to 3 significant figures. (3)

  2. Question 2Calculator · 4 marks

    A triangle has sides 10 cm, 12 cm and 15 cm.

    (a) Find its largest angle to 1 decimal place. (2)

    (b) Find its area to 3 significant figures. (2)

  3. Question 3Calculator · 3 marks

    (a) From harbour A, boat B is 12 km away on a bearing of 060∘060^\circ and boat C is 9 km away on a bearing of 140∘.140^\circ. Work out the bearing of C from B. Give your answer as a three-figure bearing to the nearest degree. You must show your working. (3)

Answers and marks

Question 1

(a) 7.24 cm

  • M1 Correct substitution into the cosine rule.
  • M1 Square-rooting a correct value of BC2BC^2.
  • A1 Correct answer: 7.24 cm.

Question 2

(a) 85.585.5°

  • M1 The largest angle is opposite the longest side; rearrange the cosine rule.
  • A1 Correct answer: 85.585.5°

(b) 59.859.8 cm²

  • M1 Use the two sides surrounding the unrounded angle.
  • A1 Correct answer: 59.859.8 cm²

Question 3

(a) 200200°

  • P1 Establishing 9×sin⁡(140)−12×sin⁡(60)9\times \sin(140)-12\times \sin(60) or an equivalent valid method.
  • P1 Establishing 9×cos⁡(140)−12×cos⁡(60)9\times \cos(140)-12\times \cos(60) or an equivalent valid method.
  • A1 Correct answer: 200200°

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Cosine rule for sides and angles

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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