Worksheets · Higher

Recurring decimals as fractions

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 4 marks

    Write each recurring decimal as a fraction in its simplest form.

    (a) 0.7˙0.\dot{7} (2)

    (b) 0.2˙7˙0.\dot{2}\dot{7} (2)

  2. Question 2Non-calculator · 5 marks

    0.2˙=290.\dot{2} = \frac{2}{9}

    (a) Use this fact to write 0.02˙0.0\dot{2} as a fraction in its simplest form. (2)

    (b) Work out 0.3˙+0.02˙0.\dot{3} + 0.0\dot{2}. Give your answer as a fraction in its simplest form. (3)

  3. Question 3Non-calculator · 3 marks

    (a) The digits a and b are non-zero. The decimal x = 0.ababab… repeats the two-digit block ab. The decimal y = 0.bababa… repeats the reversed block ba. Given x + y = 1 and x −- y = 3/11, find the two-digit integer ab. You must show your working. (3)

Answers and marks

Question 1

(a) 79\frac{7}{9}

  • M1 Writing 10x=7.777…10x = 7.777\ldots and subtracting.
  • A1 The correct answer, 79\frac{7}{9}.

(b) 311\frac{3}{11}

  • M1 Using 100x100x and subtracting to get 99x=2799x = 27.
  • A1 The correct answer, 311\frac{3}{11}.

Question 2

(a) 145\frac{1}{45}

  • M1 Dividing 29\frac{2}{9} by 10.
  • A1 The correct answer, 145\frac{1}{45}.

(b) 1645\frac{16}{45}

  • P1 Writing 0.3˙=130.\dot{3} = \frac{1}{3}.
  • P1 Adding with a common denominator of 45.
  • A1 1645\frac{16}{45}.

Question 3

(a) 6363

  • P1 Establishing (10a+b)/99+(10b+a)/99=1(10a+b)/99+(10b+a)/99=1 or an equivalent valid method.
  • P1 Establishing a−b=3a-b=3 or an equivalent valid method.
  • A1 Correct answer: 6363

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Recurring decimals as fractions

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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