Worksheets · Higher

Algebraic fractions and rational equations

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 4 marks

    Simplify fully.

    (a) Simplify fully 3x2+6xx2−4\dfrac{3x^2 + 6x}{x^2 - 4} (2)

    (b) Simplify fully 2x5÷4x215\dfrac{2x}{5} \div \dfrac{4x^2}{15} (2)

  2. Question 2Calculator · 3 marks

    (a) Simplify [(x2x^{2} −- 9)/(x2x^{2} + x −- 6)] ÷\div [(x + 3)/(x −- 1)], where x is not −3-3, 1 or 2. Give your answer as a single fraction in factorised form. (3)

  3. Question 3Non-calculator · 6 marks

    E=xx−3−18x2−9E = \dfrac{x}{x - 3} - \dfrac{18}{x^2 - 9}

    (a) Show that EE simplifies to x+6x+3\dfrac{x + 6}{x + 3}. (4)

    (b) Hence solve E=2E = 2. (2)

Answers and marks

Question 1

(a) 3xx−2\dfrac{3x}{x - 2}

  • M1 Factorising the numerator to 3x(x+2)3x(x + 2) and the denominator to (x+2)(x−2)(x + 2)(x - 2).
  • A1 3xx−2\frac{3x}{x - 2}.

(b) 32x\dfrac{3}{2x}

  • M1 Multiplying by the reciprocal 154x2\frac{15}{4x^2}.
  • A1 The correct answer, 32x\frac{3}{2x}.

Question 2

(a) ((x−3)(x−1))/((x−2)(x+3))((x - 3)(x - 1))/((x - 2)(x + 3))

  • M1 Establishing (x−3)(x+3)/((x+3)(x−2))(x-3)(x+3)/((x+3)(x-2)) or an equivalent valid method.
  • M1 Establishing x−1x+3\frac{x-1}{x+3} or an equivalent valid method.
  • A1 Correct answer: ((x−3)(x−1))/((x−2)(x+3))((x - 3)(x - 1))/((x - 2)(x + 3))

Question 3

(a) x(x+3)−18(x−3)(x+3)=(x+6)(x−3)(x−3)(x+3)=x+6x+3\frac{x(x + 3) - 18}{(x - 3)(x + 3)} = \frac{(x + 6)(x - 3)}{(x - 3)(x + 3)} = \frac{x + 6}{x + 3}

  • P1 Using the common denominator (x−3)(x+3)(x - 3)(x + 3).
  • P1 Reaching the numerator x2+3x−18x^2 + 3x - 18.
  • M1 Factorising the numerator to (x+6)(x−3)(x + 6)(x - 3).
  • A1 Cancelling (x−3)(x - 3) to reach x+6x+3\frac{x + 6}{x + 3}.

(b) x=0x = 0

  • M1 Forming x+6=2(x+3)x + 6 = 2(x + 3).
  • A1 The correct answer, x=0x = 0.

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Algebraic fractions and rational equations

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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