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Perpendicular gradients and line equations

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Non-calculator · 3 marks

    Line LL has equation y=2x−3y = 2x - 3.

    (a) Write down the gradient of a line perpendicular to LL. (1)

    (b) Find the equation of the line perpendicular to LL that passes through (4,1)(4, 1). (2)

  2. Question 2Non-calculator · 5 marks

    A is (0,0)(0,0) and B is (10,8)(10,8).

    (a) Find the perpendicular bisector of AB. (3)

    (b) Find where the perpendicular bisector meets the x-axis. (2)

  3. Question 3Non-calculator · 5 marks

    A triangle has vertices A(1,1)A(1, 1), B(4,3)B(4, 3) and C(2,6)C(2, 6).

    (a) Show that angle ABCABC is a right angle. (3)

    (b) Work out the area of triangle ABC. (2)

Answers and marks

Question 1

(a) −12-\frac{1}{2}

  • B1 The correct answer, −12-\frac{1}{2}.

(b) y=−12x+3y = -\frac{1}{2}x + 3

  • M1 Substituting (4,1)(4, 1) into y=mx+cy = mx + c with their perpendicular gradient.
  • A1 y=−12x+3y = -\frac{1}{2}x + 3 (or x+2y=6x + 2y = 6).

Question 2

(a) y=−54x+414y=-\frac{5}{4}x+\frac{41}{4}

  • M1 Find the midpoint of AB and the negative reciprocal of its gradient.
  • M1 Use the midpoint to determine the intercept.
  • A1 Correct answer: y=−54x+414y=-\frac{5}{4}x+\frac{41}{4}

(b) (41/5,0)(41/5,0)

  • M1 Set y equal to zero and solve for x.
  • A1 Correct answer: (41/5,0)(41/5,0)

Question 3

(a) Gradients 23\frac{2}{3} and −32-\frac{3}{2} multiply to −1-1.

  • M1 Finding one gradient correctly.
  • M1 Finding both gradients.
  • C1 Showing the product is −1-1 and concluding the lines are perpendicular.

(b) 6.56.5 square units

  • P1 Finding ABAB and BCBC (both 13\sqrt{13}).
  • A1 The correct answer, 6.56.5.

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Perpendicular gradients and line equations

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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