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Exponential and trigonometric graphs

3 exam-style questions. Answers and the mark for each step are on the last page.

  1. Question 1Calculator · 2 marks

    (a) A model gives the mass of a culture at times 0, 1, 2, 3 and 4 hours as 80, 120, 180, 270 and 405 grams respectively. The plotted points are joined by straight segments. Use this graph model to estimate when the mass reaches 300 grams. Give your answer to 1 decimal place. (2)

  2. Question 2Non-calculator · 4 marks

    A population model is P=40(1.5)tP=40(1.5)^t, where t is years after the initial measurement.

    (a) Find the modelled population after 3 years. (2)

    (b) Find t when the model gives P = 202.5. (2)

  3. Question 3Non-calculator · 5 marks

    sin⁡40∘=0.643\sin 40^{\circ} = 0.643, correct to 3 decimal places.

    (a) Find another angle between 0∘0^{\circ} and 360∘360^{\circ} whose sine is 0.6430.643. (1)

    (b) Find the angle between 180∘180^{\circ} and 270∘270^{\circ} whose sine is −0.643-0.643. (2)

    (c) Find the angle xx between 0∘0^{\circ} and 90∘90^{\circ} with cos⁡x=0.643\cos x = 0.643. (2)

Answers and marks

Question 1

(a) 3.23.2 hours

  • P1 Establishing 3+(300−270)/(405−270)3+(300-270)/(405-270) or an equivalent valid method.
  • A1 Correct answer: 3.23.2 hours

Question 2

(a) 135135

  • M1 Repeated percentage growth uses the multiplier raised to the number of years.
  • A1 Correct answer: 135135

(b) 44

  • M1 Divide by the initial population and recognise a power of 1.5.
  • A1 Correct answer: 44

Question 3

(a) 140∘140^{\circ}

  • B1 The correct answer, 140∘140^{\circ}.

(b) 220∘220^{\circ}

  • M1 Using 180∘+40∘180^{\circ} + 40^{\circ} or the rotational symmetry about (180,0)(180, 0).
  • A1 The correct answer, 220∘220^{\circ}.

(c) 50∘50^{\circ}

  • P1 Using cos⁡x=sin⁡(90∘−x)\cos x = \sin(90^{\circ} - x) (the cosine graph is the sine graph shifted by 90∘90^{\circ}).
  • A1 The correct answer, 50∘50^{\circ}.

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Exponential and trigonometric graphs

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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