STEP preparation

STEP questions by topic

Original problems in the papers' style, sorted into 14 topics, each with hints in stages, a worked solution and a mark scheme.

Questions12 a paper: 8 Pure, 2 Mechanics, 2 Probability and Statistics
Marking20 marks a question; your six best answers count, out of 120

The topics

Integration is free to try. Every other topic comes with the course.

TopicSection
Algebra, inequalities and functionsPure Mathematics
Sequences, series and inductionPure Mathematics
Differentiation and curve sketchingPure Mathematics
IntegrationPure Mathematics
Trigonometry and coordinate geometryPure Mathematics
Complex numbers and matricesPure Mathematics
VectorsPure Mathematics
Proof and numberPure Mathematics
Hyperbolic functions, polar curves and Maclaurin seriesPure Mathematics
Differential equationsPure Mathematics
Forces, motion and centre of massMechanics
Energy, collisions and oscillationsMechanics
Probability and discrete distributionsProbability and Statistics
Continuous distributionsProbability and Statistics

Try a problem

Integrals with a hidden symmetry

Paper 2 · Integration · Accessible · 20 marks
  1. (i)
    Let  , let gg be a continuous even function and let hh be a continuous odd function, both defined on [−a,a][-a,a]. By using the substitution  , show that ∫−aag(x)1+eh(x) dx=∫0ag(x) dx.\int_{-a}^{a}\frac{g(x)}{1+e^{h(x)}}\,\mathrm{d}x=\int_0^a g(x)\,\mathrm{d}x.
    7 marks
  2. (ii)
    Find ∫−111(1+x2)(1+ex3) dx\displaystyle\int_{-1}^{1}\frac{1}{(1+x^2)(1+e^{x^3})}\,\mathrm{d}x.
    3 marks
  3. (iii)
    Find ∫−π/3π/3sec⁡x1+etan⁡x dx\displaystyle\int_{-\pi/3}^{\pi/3}\frac{\sec x}{1+e^{\tan x}}\,\mathrm{d}x.
    4 marks
  4. (iv)
    By adapting the method of part (i) to the substitution  , find ∫0πsin⁡x1+ecos⁡x dx\displaystyle\int_{0}^{\pi}\frac{\sin x}{1+e^{\cos x}}\,\mathrm{d}x.
    6 marks

Next step

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Questions people ask

Are these real STEP questions?

No. Every problem here is original, written in the style of the papers and checked by computation and by an independent solve.